# a simple butane molecule is being investigated. # first define some colors color id=0 rgb=[1.0,1.0,1.0] color id=1 rgb=[1.0,0.0,0.0] color id=2 rgb=[0.0,1.0,0.0] color id=3 rgb=[0.0,0.0,1.0] color id=4 rgb=[0.3,0.3,0.3] # define the box box cell=[25,25,25] # ------------------------------------------ # the carbon chain scale x=1.5 y=1.5 z=1.5 particle m=21894.71 q=6.0 r=1.46 p=[0.0,0.0,0.0] x=[-4.0,0.0,0.0] c=4 id=1 particle x=[-2.0,0.0,0.0] particle x=[0.0,0.0,0.0] particle x=[2.0,0.0,0.0] # the bonding forces between the carbons interaction harmonic f=1.275 r0=2.89 { 1 2 } interaction harmonic f=1.275 r0=2.89 { 2 3 } interaction harmonic f=1.275 r0=2.89 { 3 4 } # the bond bending forces between the carbons interaction bending f=0.175 deg=112.4 { 1 2 3 4 } # then the torsional force between the carbons interaction torsional f=0.0175 n=1 deg=180.0 { 1 2 3 4 } # ------------------------------------------ # now for the hydrogen atoms on C1 translate x=-4.0 scale x=2.25 y=2.25 z=2.25 particle m=1827.81 q=1.0 r=0.701 p=[0.0,0.0,0.0] x=[1.0,0.0,0.0] c=0 id=100 particle x=[0.0,1.0,0.0] particle x=[0.0,0.0,1.0] # the H-C-H bending forces of the first CH3 interaction bending f=0.175 deg=107.7 { 100 1 101 } interaction bending f=0.175 deg=107.7 { 101 1 102 } interaction bending f=0.175 deg=107.7 { 102 1 100 } #the H-C-C bending forces of the first CH3 interaction bending f=0.175 deg=111.2 { 2 1 100 } interaction bending f=0.175 deg=111.2 { 2 1 101 } interaction bending f=0.175 deg=111.2 { 2 1 102 } # the bonding interactions of the first CH3 interaction harmonic f=1.195 r0=3.76 { 1 100 } interaction harmonic f=1.195 r0=3.76 { 1 101 } interaction harmonic f=1.195 r0=3.76 { 1 102 } # ------------------------------------------ # now for the hydrogen atoms on C2 translate x=-2.0 scale x=2.25 y=2.25 z=2.25 particle x=[1.0,0.0,0.0] id=200 particle x=[0.0,1.0,0.0] # the CH2 H-C-H bending on C2 interaction bending f=0.175 deg=106.1 { 200 2 201 } # the four CH2 C-C-H bending on C2 interaction bending f=0.175 deg=109.5 { 1 2 200 } interaction bending f=0.175 deg=109.5 { 1 2 201 } interaction bending f=0.175 deg=109.5 { 3 2 200 } interaction bending f=0.175 deg=109.5 { 3 2 201 } # the bonding interactions of the first CH2 on C2 interaction harmonic f=1.195 r0=3.76 { 2 200 } interaction harmonic f=1.195 r0=3.76 { 2 201 } # ------------------------------------------ # now for the hydrogen atoms on C3 translate x=0.0 scale x=2.25 y=2.25 z=2.25 particle x=[1.0,0.0,0.0] id=300 particle x=[0.0,1.0,0.0] # the CH2 H-C-H bending on C3 interaction bending f=0.175 deg=106.1 { 300 3 301 } # the four CH2 C-C-H bending on C3 interaction bending f=0.175 deg=109.5 { 2 3 300 } interaction bending f=0.175 deg=109.5 { 2 3 301 } interaction bending f=0.175 deg=109.5 { 4 3 300 } interaction bending f=0.175 deg=109.5 { 4 3 301 } # the bonding interactions of the second CH2 on C3 interaction harmonic f=1.195 r0=3.76 { 3 300 } interaction harmonic f=1.195 r0=3.76 { 3 301 } # ------------------------------------------ # now for the hydrogen atoms on C4 translate x=2.0 scale x=2.25 y=2.25 z=2.25 particle x=[1.0,0.0,0.0] id=400 particle x=[0.0,1.0,0.0] particle x=[0.0,0.0,1.0] # the H-C-H bending forces of the second CH3 interaction bending f=0.175 deg=107.7 { 400 4 401 } interaction bending f=0.175 deg=107.7 { 401 4 402 } interaction bending f=0.175 deg=107.7 { 402 4 400 } #the H-C-C bending forces of the second CH3 interaction bending f=0.175 deg=111.2 { 3 4 400 } interaction bending f=0.175 deg=111.2 { 3 4 401 } interaction bending f=0.175 deg=111.2 { 3 4 402 } # the bonding interactions of the first CH3 interaction harmonic f=1.195 r0=3.76 { 4 400 } interaction harmonic f=1.195 r0=3.76 { 4 401 } interaction harmonic f=1.195 r0=3.76 { 4 402 } # ------------------------------------------ # find stable situation first conformation n=10000 error=1.0E-4 maxstep=2.5 # ------------------------------------------ # then setup a constant temperature temperature k=3.166829379841521e-06 constant=293.0 tau=206.7055 # and finaly the dynamics statement, run 100 ps with steps of 0.1 fs dynamics dt=4.13411 tend=4134110.5461 t=0.0 error=3.67493E-6