# The following input file describes water according to the SPC/E model, but # allows the water to be a non-ridgid rotor. The equilibrium geometry of the water # is taken to be the one of the SPC/E model, the charges on the H's and O's and the # Lennard-Jonnes of the O-O is also taken from the SPC/E model, the OH bond stretch, # and the H-O-H bond bending potentials are taken from the Ferguson force-field. # # The obtained water force-field closely resembles the Ferguson force-field. The # difference is in the fact that our field does not have a cubic bond stretching OH # potential contirbution. Furgeson took the same functional form, with the cubic term # and used the parameters according to an SPC-like model (he used slightly different # parameter values, if you are precise about things ;-). Our field, in the # equilibrium geometry of H2O, corresponds to the SPC/E force-field. # # REFS. Ferguson: D. Ferguson, J. Comput. Chem., 16 (1995) 501. # SPC & SPC/E: H. J. C. Berendsen, J. P. M. Postma, W. F. von Gunsteren, # J. Hermans, Intermolecular Forces, B. Pullman ed., Reidel: # Dordrecht, Holland, 1981, 331-342. # # first define some colors color id=0 rgb=[1.0,1.0,1.0] color id=1 rgb=[1.0,0.0,0.0] color id=2 rgb=[0.0,1.0,0.0] color id=3 rgb=[0.0,0.0,1.0] # define the dynamical box box periodic=[25,25,25] # then a water molecule translate x=0.0 y=0.0 z=0.0 rotate deg=0 axis=[1.0,0.0,0.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=1 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for a water molecule interaction bending fcos=0.1789 deg=109.47 { 1 3 2 } interaction harmonic f=1.7450 r0=1.89 { 1 3 } interaction harmonic f=1.7450 r0=1.89 { 2 3 } # then another water molecule translate x=6.0 y=-3.0 z=0.0 rotate deg=45 axis=[1.0,0.0,0.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=4 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for the water molecule interaction bending fcos=0.1789 deg=109.47 { 4 6 5 } interaction harmonic f=1.7450 r0=1.89 { 4 6 } interaction harmonic f=1.7450 r0=1.89 { 5 6 } # then another water molecule translate x=0.0 y=-6.0 z=3.0 rotate deg=90 axis=[1.0,0.0,0.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=7 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for the water molecule interaction bending fcos=0.1789 deg=109.47 { 7 9 8 } interaction harmonic f=1.7450 r0=1.89 { 7 9 } interaction harmonic f=1.7450 r0=1.89 { 9 8 } # then another water molecule translate x=-10.0 y=2.0 z=3.0 rotate deg=45 axis=[0.0,1.0,0.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=10 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for the water molecule interaction bending fcos=0.1789 deg=109.47 { 10 12 11 } interaction harmonic f=1.7450 r0=1.89 { 10 12 } interaction harmonic f=1.7450 r0=1.89 { 12 11 } # then another water molecule translate x=-4.0 y=-4.0 z=2.0 rotate deg=81 axis=[0.0,0.0,1.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=13 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for the water molecule interaction bending fcos=0.1789 deg=109.47 { 13 15 14 } interaction harmonic f=1.7450 r0=1.89 { 13 15 } interaction harmonic f=1.7450 r0=1.89 { 15 14 } # then another water molecule translate x=-4.0 y=4.0 z=-2.0 rotate deg=14 axis=[1.0,0.0,1.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=16 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for the water molecule interaction bending fcos=0.1789 deg=109.47 { 16 18 17 } interaction harmonic f=1.7450 r0=1.89 { 16 18 } interaction harmonic f=1.7450 r0=1.89 { 18 17 } # then another water molecule translate x=-2.0 y=-5.0 z=-3.0 rotate deg=95 axis=[0.0,1.0,1.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=19 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for the water molecule interaction bending fcos=0.1789 deg=109.47 { 19 21 20 } interaction harmonic f=1.7450 r0=1.89 { 19 21 } interaction harmonic f=1.7450 r0=1.89 { 21 20 } # then another water molecule translate x=-1.0 y=-2.0 z=0.0 rotate deg=95 axis=[1.0,1.0,1.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=22 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for the water molecule interaction bending fcos=0.1789 deg=109.47 { 22 24 23 } interaction harmonic f=1.7450 r0=1.89 { 22 24 } interaction harmonic f=1.7450 r0=1.89 { 24 23 } # then another water molecule translate x=-3.0 y=-2.0 z=-1.0 rotate deg=20 axis=[1.0,1.0,1.0] particle m=1827.8 q=0.4238 r=0.701 p=[0.0,0.0,0.0] x=[0.0,0.0,0.0] c=0 id=25 particle x=[0.0,6.0,0.0] particle m=29165.1 q=-0.8476 r=1.38 x=[0.0,3.0,3.0] c=1 # now the interactions for the water molecule interaction bending fcos=0.1789 deg=109.47 { 25 27 26 } interaction harmonic f=1.7450 r0=1.89 { 25 27 } interaction harmonic f=1.7450 r0=1.89 { 27 26 } # total O's interaction interaction lennardjones f=2.4765E-4 r0=6.71554 { 3 6 9 12 15 18 21 24 27 } # total coulomb potential interaction coulomb f=1.0 { all } # find stable situation first conformation n=10000 error=1.0E-10 maxstep=2.5 # setup the initial temperature temperature k=3.166829379841521e-06 constant=273 tau=206.7055 # and finaly the dynamics statement, run for 100 ps with steps of 0.1 fs dynamics dt=4.13411 tend=4134110.5461 t=0.0 error=3.67493E-6